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ES6 defaults / overrides pattern
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| // The defaults / overrides pattern in ES6 | |
| // This *looks like* it should work, but | |
| // prints, "yay, undefined" | |
| /* | |
| let defaults = { | |
| bar: 'no', | |
| baz: 'works!' | |
| }; | |
| function foo ({ bar, baz } = defaults) { | |
| return(`${bar}, ${baz}`); | |
| } | |
| console.log(foo({ | |
| bar: 'yay' | |
| })); | |
| */ | |
| // So you really have to do this: | |
| let defaults = { | |
| bar: 'no', | |
| baz: 'works!' | |
| }; | |
| function foo (options) { | |
| let settings = Object.assign({}, defaults, options); | |
| let { bar, baz } = settings; | |
| return(`${bar}, ${baz}`); | |
| } | |
| console.log(foo({ | |
| bar: 'yay' | |
| })); | |
| // Equivalent to ES5: | |
| // This bit needs to be polyfilled, | |
| // Or use $.extend(), _.extend(), | |
| // lodash/object/assign aka _.assign() | |
| // or equivalent. | |
| var assign = Object.assign; | |
| var defaults2 = { | |
| bar: 'no', | |
| baz: 'works!' | |
| }; | |
| function foo2 (options) { | |
| var settings = assign({}, defaults2, options), | |
| bar = settings.bar, | |
| baz = settings.baz; | |
| return(bar + ', ' +baz); | |
| } | |
| console.log(foo2({ | |
| bar: 'yay' | |
| })); |
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