{ "cells": [ { "cell_type": "markdown", "id": "d9d762a0", "metadata": {}, "source": [ "### Property of Beatty sequence and its complementary:\n", "Every positive integer belongs to exactly one of ${\\mathcal {B}}_{r}^{(i)}$ or ${\\mathcal {B}}_{s}^{(i)}$.\n", "\n", "\n", " \n", "$S(n,r) + S(\\lfloor{\\frac{{\\mathcal {B}}_{r}^{(n)}}{s}}\\rfloor,s) = \\sum_{i=1}^{{\\mathcal {B}}_{r}^{(n)}} i = \\frac{{\\mathcal {B}}_{r}^{(n)}({\\mathcal {B}}_{r}^{(n)}+1)}{2} \\qquad \\textbf{(ii)}$\n", "\n", "$\\stackrel{using \\; (i)}{=>} S(n,r) + S(\\lfloor{\\frac{{\\mathcal {B}}_{r}^{(n)}}{s}}\\rfloor,r) + \\lfloor{\\frac{{\\mathcal {B}}_{r}^{(n)}}{s}}\\rfloor(\\lfloor{\\frac{{\\mathcal {B}}_{r}^{(n)}}{s}}\\rfloor+1)$\n", "\n", "$\\stackrel{using \\; (ii)}{=>} S(n,r) = \\frac{{\\mathcal {B}}_{r}^{(n)}({\\mathcal {B}}_{r}^{(n)}+1)}{2} - S(\\lfloor{\\frac{{\\mathcal {B}}_{r}^{(n)}}{s}}\\rfloor,r) - \\lfloor{\\frac{{\\mathcal {B}}_{r}^{(n)}}{s}}\\rfloor(\\lfloor{\\frac{{\\mathcal {B}}_{r}^{(n)}}{s}}\\rfloor+1)$" ] } ], "metadata": { "kernelspec": { "display_name": "foobar", "language": "python", "name": "foobar" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.13" } }, "nbformat": 4, "nbformat_minor": 5 }