You are given an array of characters arr that consists of sequences of characters separated by space characters. Each space-delimited sequence of characters defines a word.

Implement a function reverseWords that reverses the order of the words in the array in the most efficient manner.

Explain your solution and analyze its time and space complexities.

input:  arr = [ 'p', 'e', 'r', 'f', 'e', 'c', 't', '  ',
                'm', 'a', 'k', 'e', 's', '  ',
                'p', 'r', 'a', 'c', 't', 'i', 'c', 'e' ]

output: [ 'p', 'r', 'a', 'c', 't', 'i', 'c', 'e', '  ',
          'm', 'a', 'k', 'e', 's', '  ',
          'p', 'e', 'r', 'f', 'e', 'c', 't' ]

function reverseWords(arr) {
  const str = arr.join('').replace(',',''); //Convert arry to string to split
  const input = str.split(' '); // Split into words
  const ans =  input.reduceRight((a,b)=> a.concat((b+" ").split('')), []); //revers words add space back
  return ans.slice(0,-1); //trim last space.
}

function reverseWords(arr) {
  const wordsArray = arr.join('').replace(',','').split(' '); //Split array into words
  return wordsArray.reduceRight((a,b)=> [...a, ...b, " "],[]).slice(0,-1); // Reverse words, break into chars & trim last space
}

Input:

[" "," "] Expected:

[" "," "] Actual:

[ ' ', ' ' ]