Laura Shapiro lshapz

Strings

None of the string methods modify this – they always return fresh strings.

charAt(pos: number): string ^ES1

Returns the character at index pos, as a string (JavaScript does not have a datatype for characters). str[i] is equivalent to str.charAt(i) and more concise (caveat: may not work on old engines).

Open in a new tab all to-be-deleted github repositores (Use the mouse’s middle click or Ctrl + Click) https://github.com/username?tab=repositories
Use one tab https://chrome.google.com/webstore/detail/onetab/chphlpgkkbolifaimnlloiipkdnihall to shorten them to a list.
Save that list to some path
The list should be in the form of “ur_username\repo_name” per line. Use regex search (Sublime text could help). Search for ' |.*' and replace by empty.

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	node {
	echo 'Results included as an inline comment exactly how they are returned as of Jenkins 2.121, with $BUILD_NUMBER = 1'
	echo 'No quotes, pipeline command in single quotes'
	sh 'echo $BUILD_NUMBER' // 1
	echo 'Double quotes are silently dropped'
	sh 'echo "$BUILD_NUMBER"' // 1
	echo 'Even escaped with a single backslash they are dropped'
	sh 'echo \"$BUILD_NUMBER\"' // 1
	echo 'Using two backslashes, the quotes are preserved'
	sh 'echo \\"$BUILD_NUMBER\\"' // "1"

	function mapValues(obj, fn) {
	return Object.keys(obj).reduce((result, key) => {
	result[key] = fn(obj[key], key);
	return result;
	}, {});
	}

	function pick(obj, fn) {
	return Object.keys(obj).reduce((result, key) => {
	if (fn(obj[key])) {

	# Sample implementation of quicksort and mergesort in ruby
	# Both algorithm sort in O(n * lg(n)) time
	# Quicksort works inplace, where mergesort works in a new array

	def quicksort(array, from=0, to=nil)
	if to == nil
	# Sort the whole array, by default
	to = array.count - 1
	end