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Monte carlo simulator finding the odds that an 8-digit decimal number has exactly 4 of the same digit.
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| #!/usr/bin/python | |
| import random | |
| total = 0; | |
| good = 0; | |
| for n in xrange(1,100000000): | |
| i = random.randint(0,99999999) | |
| s = "{0:0>8}".format(i); | |
| a = {} | |
| for c in list(s): | |
| if c in a.keys(): | |
| a[c]+=1; | |
| else: | |
| a[c]=1; | |
| if 4 in a.values(): | |
| good+=1; | |
| if n % 100000 == 0: | |
| ratio = good/float(n) | |
| print "%.4f = %d / %d"%(ratio,good,n) |
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