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Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.
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| const expect = (actual, expected) => { | |
| if (actual !== expected) { | |
| console.log(`Expected ${actual} to equal ${expected}`); | |
| } | |
| }; | |
| var containsDuplicate = function (nums) { | |
| var map = new Map(); | |
| for (const elm of nums) { | |
| if (map.has(elm)) { | |
| return true; | |
| } | |
| map.set(elm, true); | |
| } | |
| return false; | |
| }; | |
| expect(containsDuplicate([1, 2, 3, 1]), true); | |
| expect(containsDuplicate([1, 2, 3, 4]), false); |
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| /* | |
| https://leetcode.com/problems/contains-duplicate/ | |
| Example 1: | |
| Input: nums = [1,2,3,1] | |
| Output: true | |
| Example 2: | |
| Input: nums = [1,2,3,4] | |
| Output: false | |
| Example 3: | |
| Input: nums = [1,1,1,3,3,4,3,2,4,2] | |
| Output: true | |
| Constraints: | |
| 1 <= nums.length <= 105 | |
| -109 <= nums[i] <= 109 | |
| */ | |
| const expect = (actual, expected) => { | |
| if (actual !== expected) { | |
| console.log(`Expected ${actual} to equal ${expected}`); | |
| } | |
| }; | |
| var containsDuplicate = function (nums) { | |
| var map = new Map(); | |
| for (const elm of nums) { | |
| if (map.has(elm)) { | |
| return true; | |
| } | |
| map.set(elm, true); | |
| } | |
| return false; | |
| }; | |
| expect(containsDuplicate([1, 2, 3, 1]), true); | |
| expect(containsDuplicate([1, 2, 3, 4]), false); |
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