test

次の微分をせよ．

(1) \(\dfrac{d}{dx}\ x^2+\dfrac{1}{x}+1=\) [[input:ans1]] [[validation:ans1]]

(2) \(\dfrac{d}{dx}\ \sin(x^2+1)=\) [[input:ans2]] [[validation:ans2]]

]]> 1 0.1 0 2020120600 T1 : diff(x^2+1/x+1,x) T2 : diff(sin(x^2+1),x) 1 0 0 よくできました。正解です！]]> 部分的に正解です。]]> 間違いです。]]> none 1 i cos-1 lang [ ans1 algebraic T1 10 1 0 0 1 0 0 1 1 ans2 algebraic T2 10 1 0 0 1 0 0 1 1 prt1 1.0000000 1 1 0 AlgEquiv ans1 T1 0 = 1.0000000 -1 prt1-1-T = 0.0000000 -1 prt1-1-F prt2 1.0000000 1 1 0 AlgEquiv ans2 T2 0 = 1.0000000 -1 prt2-1-T = 0.0000000 -1 prt2-1-F