Last active
July 30, 2025 03:53
-
-
Save axionbuster/66f4c7e4d0ce1d56042cb3c596385076 to your computer and use it in GitHub Desktop.
Revisions
-
axionbuster revised this gist
Jul 30, 2025 . 1 changed file with 1 addition and 1 deletion.There are no files selected for viewing
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode charactersOriginal file line number Diff line number Diff line change @@ -101,4 +101,4 @@ main = do another test. 1 + 285 + ... + 285 ^ 4294967296 = 3364 (mod 7731) -} -- blazingly fast! -
axionbuster revised this gist
Jul 30, 2025 . 1 changed file with 64 additions and 0 deletions.There are no files selected for viewing
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode charactersOriginal file line number Diff line number Diff line change @@ -1,3 +1,5 @@ -- https://stackoverflow.com/a/9486650 (no relation with author) import Control.Monad import Data.Foldable import GHC.Natural @@ -15,6 +17,7 @@ geo modulus = go squared = (`power` 2) plus x y = (x + y) `mod` modulus times x y = (x * y) `mod` modulus -- you can trust me, it's OK to right-fold. go r 0 = 1 go r n = case n `divMod` 2 of (_, 0) -> 1 `plus` (r `times` go r (n - 1)) @@ -38,3 +41,64 @@ main = do modulo2 = 7731 printf "another test. 1 + %v + ... + %v ^ %v = %v (mod %v)\n" base2 base2 count2 (geo modulo2 base2 count2) modulo2 {- === Modulo 2 === 1 + 2 + ... + 2 ^ 2 = 1 (mod 2) 1 + 2 + ... + 2 ^ 3 = 1 (mod 2) 1 + 2 + ... + 2 ^ 4 = 1 (mod 2) === Modulo 3 === 1 + 2 + ... + 2 ^ 2 = 1 (mod 3) 1 + 2 + ... + 2 ^ 3 = 0 (mod 3) 1 + 2 + ... + 2 ^ 4 = 1 (mod 3) === Modulo 4 === 1 + 2 + ... + 2 ^ 2 = 3 (mod 4) 1 + 2 + ... + 2 ^ 3 = 3 (mod 4) 1 + 2 + ... + 2 ^ 4 = 3 (mod 4) === Modulo 5 === 1 + 2 + ... + 2 ^ 2 = 2 (mod 5) 1 + 2 + ... + 2 ^ 3 = 0 (mod 5) 1 + 2 + ... + 2 ^ 4 = 1 (mod 5) === Modulo 6 === 1 + 2 + ... + 2 ^ 2 = 1 (mod 6) 1 + 2 + ... + 2 ^ 3 = 3 (mod 6) 1 + 2 + ... + 2 ^ 4 = 1 (mod 6) === Modulo 7 === 1 + 2 + ... + 2 ^ 2 = 0 (mod 7) 1 + 2 + ... + 2 ^ 3 = 1 (mod 7) 1 + 2 + ... + 2 ^ 4 = 3 (mod 7) === Modulo 8 === 1 + 2 + ... + 2 ^ 2 = 7 (mod 8) 1 + 2 + ... + 2 ^ 3 = 7 (mod 8) 1 + 2 + ... + 2 ^ 4 = 7 (mod 8) === Modulo 9 === 1 + 2 + ... + 2 ^ 2 = 7 (mod 9) 1 + 2 + ... + 2 ^ 3 = 6 (mod 9) 1 + 2 + ... + 2 ^ 4 = 4 (mod 9) === Modulo 10 === 1 + 2 + ... + 2 ^ 2 = 7 (mod 10) 1 + 2 + ... + 2 ^ 3 = 5 (mod 10) 1 + 2 + ... + 2 ^ 4 = 1 (mod 10) === Modulo 11 === 1 + 2 + ... + 2 ^ 2 = 7 (mod 11) 1 + 2 + ... + 2 ^ 3 = 4 (mod 11) 1 + 2 + ... + 2 ^ 4 = 9 (mod 11) === Modulo 12 === 1 + 2 + ... + 2 ^ 2 = 7 (mod 12) 1 + 2 + ... + 2 ^ 3 = 3 (mod 12) 1 + 2 + ... + 2 ^ 4 = 7 (mod 12) another test. 1 + 285 + ... + 285 ^ 4294967296 = 3364 (mod 7731) -} -- very fast! -
axionbuster created this gist
Jul 30, 2025 .There are no files selected for viewing
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode charactersOriginal file line number Diff line number Diff line change @@ -0,0 +1,40 @@ import Control.Monad import Data.Foldable import GHC.Natural import Prelude hiding (exp) import Text.Printf type N = Natural -- geometric sum (1 + r + r^2 + ... + r ^ n). -- order: geo [modulus] [base] [last exponent, inclusive]. geo :: N -> N -> N -> N geo modulus = go where power x y = powModNatural x y modulus squared = (`power` 2) plus x y = (x + y) `mod` modulus times x y = (x * y) `mod` modulus go r 0 = 1 go r n = case n `divMod` 2 of (_, 0) -> 1 `plus` (r `times` go r (n - 1)) (q, _) -> (1 `plus` r) `times` go (squared r) q main :: IO () main = do let base = 2 forM_ [2..12] $ \mo -> do printf "=== Modulo %v ===\n" mo forM_ [2..4] $ \po -> do let exp = sum (map (\i -> powModNatural base i mo) [0..po]) `mod` mo get = geo mo base po printf "1 + %v + ... + %v ^ %v = %v (mod %v)" base base po (geo mo 2 po) mo unless (exp == get) $ do printf " (BAD! exp = %v)" exp putStrLn "" putStrLn "" let base2 = 285 count2 = 2 ^ (32 :: Int) modulo2 = 7731 printf "another test. 1 + %v + ... + %v ^ %v = %v (mod %v)\n" base2 base2 count2 (geo modulo2 base2 count2) modulo2