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Palindrome checker
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| import Foundation | |
| // Requirements: | |
| // ignore case, whitespace, and punctuation | |
| // check from each end of the string | |
| // deal with even or odd amount of characters | |
| func canBePalindrome(_ string: String) -> Bool { | |
| var preparedString = string.lowercased() | |
| // remove spaces, common punctuation | |
| preparedString = preparedString.filter { $0 != " " } | |
| preparedString = preparedString.filter { $0 != "." } | |
| preparedString = preparedString.filter { $0 != "," } | |
| print(preparedString) | |
| return preparedString == String(preparedString.reversed()) | |
| } | |
| // Test Cases | |
| canBePalindrome("tacocat") // should return true | |
| canBePalindrome("daily") // should return false | |
| canBePalindrome("a") // should return true | |
| canBePalindrome("aa") // should return true | |
| canBePalindrome("hannah") // should return true | |
| canBePalindrome("abc") // should return false | |
| canBePalindrome("Racecar") | |
| canBePalindrome("A man, a plan, a can ... na canal panama.") | |
| // I was starting with something like this, until I realized I could just reverse the whole string: | |
| //let stringBeginning = "" | |
| //let stringEnd = "" | |
| //if preparedString.count % 2 == 0 { | |
| // //even | |
| // for letter in | |
| //} else { | |
| // //odd | |
| //} | |
| // trying my own string reversing function: | |
| func reversedString(_ string: String) -> String { | |
| var reversedString = "" | |
| for character in string { | |
| reversedString.insert(character, at: reversedString.startIndex) | |
| } | |
| return reversedString | |
| } | |
| reversedString("reversed string") |
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