Helio Junior heliocarbex

Using Node.js With Django

When writing django apps it's easy to ignore the organization of your front end code. Often, these backend coders will just write a static js and css file, stick it in the static directory, and call it a day.

You can also build them as two completely independent parts. With a complex gulp build routine independent of the django app. But if you don't know gulp, node, or those kinds of systems it can be a daunting process to get started with.

Enter django-compressor-toolkit (the name doesn't quite roll off the tongue).

Setting Up Django-Compressor-Toolkit

Using django-compressor and django-compressor-toolkit you can write Javascript ES6 code with all its fancy import/export logic or style your pages with sass instead of css, and leave your deploy routine largely untouched.

Git tips

Show repositories and upstream remote branches

git branch -vv

Set a local branch track a remote

upstream: remote
foo: local branch

git branch -u upstream/foo

This is a SCRIPT-8 cassette.

	'''
	Suppose the following structure:

	project/
	main.py
	module/
	my_module.py
	test/
	test_module.py

	from selenium.webdriver.common.by import By
	from selenium.webdriver.support import expected_conditions as EC

	D_EC={
	"click":EC.element_to_be_clickable,
	"presence":EC.presence_of_element_located,
	"visible":EC.visibility_of,
	"select":EC.element_to_be_selected,
	"state":EC.element_located_selection_state_to_be,
	"invisible":EC.invisibility_of_element,

	<!-- Select all elements with the name message in the id-->
	Xpath=//*[contains(@id,'message')]

	<!-- Select all elements with the text "here" in the text-->
	Xpath=//*[contains(text(),'here')]

	<span>
	here
	</span>

	# Mode 1
	new_func='def next_element(x):\n return x+1'
	the_code=compile(new_func,'test','exec')
	exec(the_code)
	next_element(1)

	#Mode 2
	new_func='def next_element(x):\n return x+1'
	exec(new_function)
	next_element(1)

	function svg2img(){
	var svg = document.querySelector('svg');
	var xml = new XMLSerializer().serializeToString(svg);
	var svg64 = btoa(xml); //for utf8: btoa(unescape(encodeURIComponent(xml)))
	var b64start = 'data:image/svg+xml;base64,';
	var image64 = b64start + svg64;
	return image64;
	};svg2img()

	//Got from https://stackoverflow.com/questions/3975499/convert-svg-to-image-jpeg-png-etc-in-the-browser#answer-53409434

	import operator
	import itertools

	listax=[('2019-02-19', 'Customer', 'Virtual Network', 1.8568612344799997), ('2019-02-19', 'Customer', 'Virtual Network', 1.8963689203199998)]


	def accumulate(lista):
	it = itertools.groupby(lista, operator.itemgetter(0,1,2))
	for key, subiter in it:
	yield key, sum(float(item[3]) for item in subiter)

	en:
	pagseguro:
	errors:
	'bad_request': 'Bad request'
	'5003': 'bank network error'
	'10000': 'invalid creditcard brand'
	'10001': "creditcard number with invalid length"
	'10002': "invalid date format"
	'10003': "invalid security field"
	'10004': "cvv is mandatory"