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ihappyk / Generic keys
Created December 26, 2023 09:50 — forked from h4x0r-dz/Generic keys
(?i)((access_key|access_token|admin_pass|admin_user|algolia_admin_key|algolia_api_key|alias_pass|alicloud_access_key|amazon_secret_access_key|amazonaws|ansible_vault_password|aos_key|api_key|api_key_secret|api_key_sid|api_secret|api.googlemaps AIza|apidocs|apikey|apiSecret|app_debug|app_id|app_key|app_log_level|app_secret|appkey|appkeysecret|application_key|appsecret|appspot|auth_token|authorizationToken|authsecret|aws_access|aws_access_key_id|aws_bucket|aws_key|aws_secret|aws_secret_key|aws_token|AWSSecretKey|b2_app_key|bashrc password|bintray_apikey|bintray_gpg_password|bintray_key|bintraykey|bluemix_api_key|bluemix_pass|browserstack_access_key|bucket_password|bucketeer_aws_access_key_id|bucketeer_aws_secret_access_key|built_branch_deploy_key|bx_password|cache_driver|cache_s3_secret_key|cattle_access_key|cattle_secret_key|certificate_password|ci_deploy_password|client_secret|client_zpk_secret_key|clojars_password|cloud_api_key|cloud_watch_aws_access_key|cloudant_password|cloudflare_api_key|cloudflare_auth_k
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ihappyk / FrequencyNumber.md
Last active January 15, 2017 05:57
Program to find Frequency of number occurs more than 2

#Program to find Frequency of number occurs more than 2

/*Input -> Output: {1,2,3,4} ->0 {1,1,2,3,4,4,4} ->2 {1,1,2,3,1,1,1,1} ->2 {2,2,2,4,6}->1 {1,1,1,1}->1 */




  


  




    


          
    

      

        
        

          

              @ihappyk
          

          

            
                ihappyk
                / DuplicateNumber.Algorithm
            
            

              Created
              January 24, 2016 09:37
            

              
                Finding Duplicate Number in Natural Numbers Algorithm with O(n) + O(1)
              
          

        

      

        

  

    
    


        



  


  

        

          
          

        

        

          
            Step 1: Start
        

        

          
            Step 2: Declare variables n,i,duplicateNumber,sum and number array.
        

        

          
            Step 3: Read variables  n,i and number array.
        

        

          
            Step 4: sum = find the sum of all elements.
        

        

          
                    duplicateNumber = sum - (highestNumber*(highestNumber+1)/2);
        

        

          
            Step 5: print duplicateNumber      
        

        

          
            Step 5: Stop