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December 27, 2018 11:18
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模拟takeLatest，处理竞态问题
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| function takeLatest(asyncFunc) { | |
| let index = 0; | |
| return (...argv) => { | |
| function execNext(func, reqIndex) { | |
| return (...argv2) => { | |
| if (reqIndex === index) { | |
| func.call(this, ...argv2); | |
| } | |
| }; | |
| } | |
| return new Promise((resolve, reject) => { | |
| index++; | |
| asyncFunc.call(this, ...argv).then(execNext(resolve, index), execNext(reject, index)); | |
| }); | |
| }; | |
| } | |
| // 异步函数 | |
| const timeout = name => | |
| new Promise(resolve => { | |
| setTimeout(() => { | |
| resolve(name); | |
| }, 500); | |
| }); | |
| const a = takeLatest(timeout); | |
| // 模拟频繁触发 | |
| for (let index = 0; index < 4; index++) { | |
| a(index).then(n => { | |
| // todo: 处理结果 | |
| console.log(n); | |
| }); | |
| } |
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