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January 17, 2019 23:59
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LaTeX template for Circuits&Signals lab reports
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| %Unnas Hussain | |
| %This is mostly just so I have this Preamble set up somewhere, the actual document stuff | |
| %isn't that important except for stuff like tabs and good tables and equations and stuff | |
| \documentclass[letterpaper,12pt]{article} | |
| \usepackage{caption} | |
| \usepackage{float} | |
| \usepackage{amsmath} %for align | |
| \usepackage{fancyhdr} %for margin and footer stuff | |
| \usepackage[margin=1.0in]{geometry} | |
| \usepackage{graphicx} | |
| \graphicspath{{./images//}} %put images in ./images | |
| \pagestyle{fancy} | |
| \fancyhf{} % clear all header and footers | |
| \rhead{Unnas Hussain \\ EECE 2150: Circuits \& Signals} | |
| \renewcommand{\headrulewidth}{0.4pt} | |
| \setlength{\footskip}{20pt} | |
| \rfoot{\thepage} | |
| \title{Lab 1 Report} | |
| \author{Unnas Hussain} | |
| \date{\parbox{\linewidth}{\centering% | |
| Experiment Conducted: January 10, 2019\endgraf\bigskip\bigskip\bigskip | |
| EECE2150: Circuits \& Signals: Biomedical Applications\endgraf\medskip | |
| Section 34324 (MWR 1:35)}} | |
| \begin{document} | |
| \maketitle | |
| \newpage | |
| \section*{$\>\>\>$Part 1} | |
| \begin{figure}[H] | |
| % \caption{Protoboard Worksheet for Circuit \#1}\centering | |
| % \includegraphics[scale=1.0]{circuit1} | |
| \end{figure} | |
| \subsection*{$\>\>\>$1.1 Blank Sub Section} | |
| \section*{$\>\>\>$Part 2- Table} | |
| \begin{table}[H] \centering | |
| \caption{Measurments Across Elements} | |
| \begin{tabular}{c|c|c} | |
| Element & Resistance[$\Omega$] & Voltage[V]\\ | |
| \hline | |
| LED 1 (green) & & 2.011\\ | |
| LED 2 (yellow) & & 2.0148\\ | |
| Res 1 & 510 & 4.968\\ | |
| Res 2 & 510 & 4.975\\ | |
| \end{tabular} | |
| \end{table} | |
| $\>\>\>$The KVL states that within a closed loop, the sum of all of the voltages is zero. In this circuit, this means that the sum of the voltage drop across each element should be equal to the supplied voltage ($9\ volts$). | |
| \section*{$\>\>\>$Part 3 - Equation} | |
| \begin{equation} | |
| Supplied\ Voltage = \sum{}^{} voltage\ of\ each\ element | |
| \end{equation} | |
| We measured the voltages across the LED's in series. For the resistors in parallel, since voltage is consistent across parallel resistors, we know that the equivalent voltage of the resistors for the whole circuit is equal to the average of the two voltages measured across each individual resistor ($4.9715\ volts$). So $R_{eq} * I = 4.9715\ volts$ | |
| \begin{align*} | |
| 9 | |
| &= V_{LED1} + V_{LED2} + R_{eq}*I\\ | |
| &= 2.011 + 2.0148 + 4.9715\\ | |
| &\approx 8.9973 | |
| \end{align*} | |
| We did not find any negative voltages, which means that multimeter terminals were connected in the direction of the current in the circuit. | |
| \end{document} |
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